Hi Doug,

> Ok guys here is the maths.
<snip>
> So the probability of getting the whole 5 is:
>
> 0.07 x 0.01 x .5 x .5 x .5 = .0000875 = .00875 percent
> or about 1 in 11,000

Umm, that's not the maths. Sure, if there were only 5 domains names
available and he was to get ALL of them your math is correct. The true
situation is that there were more available and he only nabbed a portion
(25%?) of them.

ie. If 100 domain names were available and I was one of 100 applications for
each then the probability that I would get *a* domain name is 1 (100 x 1/100
= 1), not 0.01 as per your calculations. The chance that I'd get the first 2
would be 0.01 x 0.01 = 0.0001 but the chance that I'd get *any* two would be
50%.

If Marr had 7 applications in each of 20 domains and there were 100
applications in total for each then he'd likely get 20 * (7/100) = 1.4
domain names. With fewer applications on some of the names he'd likely get
more.

Regards,
Jarrod Hollingworth
Software Development Manager
--
AIMTec Pty Ltd. http://www.aimtec.com.au
Unit 5, 861 Doncaster Rd, Doncaster East
Victoria, Australia 3109
Tel: +61-(0)3-9848-8636
Fax: +61-(0)3-9848-5644